Python中计算一致字符串个数的程序
假设我们有一个由不同字符组成的字符串s，并且还有一个名为words的字符串数组。当字符串中的所有字符都出现在字符串s中时，该字符串是一致的。我们必须找到数组单词中存在的一致字符串的数量。
因此，如果输入像s="px",words=["ad","xp","pppx","xpp","apxpa"]，那么输出将是3，因为只有三个字符串'p'和'x',["xp","pppx","xpp"]。
示例(Python)
让我们看看以下实现以获得更好的理解-
def solve(s, words):
count = 0
for i in range(len(words)):
for j in range(len(words[i])):
if words[i][j] not in s:
break
else:
count += 1
return count
s= "px"
words = ["ad","xp","pppx","xpp","apxpa"]
print(solve(s, words))输入
"px", ["ad","xp","pppx","xpp","apxpa"]输出结果
3