用 Python 编写一个程序来删除给定 DataFrame 中的一列或多列
假设你有一个数据框，
one two three 0 1 2 3 1 4 5 6
删除单列的结果是，
two three 0 2 3 1 5 6
在多列之后删除的结果是，
three 0 3 1 6
为了解决这个问题，我们将按照下面给出的步骤-
解决方案1
定义数据框
使用以下方法删除特定列，
del df['one']
例子
让我们看下面的代码以获得更好的理解-
import pandas as pd
data = [[1,2,3],[4,5,6]]
df = pd.DataFrame(data,columns=('one','two','three'))
print("Before deletion\n", df)
del df['one']
print("After deletion\n", df)输出
Before deletion one two three 0 1 2 3 1 4 5 6 After deletion two three 0 2 3 1 5 6
解决方案2
定义数据框
使用pop函数删除特定列。它定义如下
df.pop('one')例子
import pandas as pd
data = [[1,2,3],[4,5,6]]
df = pd.DataFrame(data,columns=('one','two','three'))
print("Before deletion\n", df)
df.pop('one')
print("After deletion\n", df)输出
Before deletion one two three 0 1 2 3 1 4 5 6 After deletion two three 0 2 3 1 5 6
解决方案3
定义数据框
应用以下方法删除多列，
df.drop(columns=['one','two'],inplace = True)
例子
import pandas as pd
data = [[1,2,3],[4,5,6]]
df = pd.DataFrame(data,columns=('one','two','three'))
print("Before deletion\n ", df)
df.drop(columns=['one','two'],inplace = True)
print("After deleting two columns\n", df)输出
Before deletion one two three 0 1 2 3 1 4 5 6 After deletion two three 0 2 3 1 5 6 After deleting two columns three 0 3 1 6
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