Python中的矩阵乘法
对于两个矩阵的乘法A和B,在A柱的数量应该等于在B.行为了得到乘积矩阵的元素的数量,我们取第i个A的行和k个B的柱,将它们逐个元素相乘并取所有这些乘积的总和。
在Python中将两个矩阵相乘的程序
import random m1=input("Enter No. of rows in the first matrix: ") n1=input("Enter No. of columns in the first matrix: ") a = [[random.random() for col in range(n1)] for row in range(m1)] for i in range(m1): for j in range(n1): a[i][j]=input()m2=input ("Enter No. of rows in the second matrix: ") n2=input ("Enter No. of columns in the second matrix: ") b = [[random.random() for col in range(n2)] for row in range(m2)] for i in range(m2): for j in range(n2): b[i][j]=input()c=[[random.random()for col in range(n2)]for row in range(m1)] if (n1==m2): for i in range(m1): for j in range(n2): c[i][j]=0 for k in range(n1): c[i][j]+=a[i][k]*b[k][j] print c[i][j],'\t', print else: print "Multiplication not possible"
输出结果
Enter No. of rows in the first matrix: 3 Enter No. of columns in the first matrix: 2 1 2 3 4 5 6 Enter No. of rows in the second matrix: 2 Enter No. of columns in the second matrix: 3 1 2 3 4 5 6 Output: 9 12 15 19 26 33 29 40 51