有没有办法选择在MySQL中部分匹配的值？
要部分匹配，请使用LIKE运算符。让我们首先创建一个表-
mysql> create table DemoTable806( StudentId int NOT NULL AUTO_INCREMENT PRIMARY KEY, StudentName varchar(100), StudentSubject varchar(100) );
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable806(StudentName,StudentSubject) values('Chris','Java in Depth With Data Structure');
mysql> insert into DemoTable806(StudentName,StudentSubject) values('Robert','Introduction to MySQL');
mysql> insert into DemoTable806(StudentName,StudentSubject) values('Bob','C++ in Depth With Data Structure And Algorithm');
mysql> insert into DemoTable806(StudentName,StudentSubject) values('Adam','Introduction to MongoDB');使用select语句显示表中的所有记录-
mysql> select *from DemoTable806;
这将产生以下输出-
+-----------+-------------+------------------------------------------------+ | StudentId | StudentName | StudentSubject | +-----------+-------------+------------------------------------------------+ | 1 | Chris | Java in Depth With Data Structure | | 2 | Robert | Introduction to MySQL | | 3 | Bob | C++ in Depth With Data Structure And Algorithm | | 4 | Adam | Introduction to MongoDB | +-----------+-------------+------------------------------------------------+ 4 rows in set (0.00 sec)
以下是查询以选择部分匹配的值-
mysql> select *from DemoTable806 where StudentSubject LIKE '%Depth%';
这将产生以下输出-
+-----------+-------------+------------------------------------------------+ | StudentId | StudentName | StudentSubject | +-----------+-------------+------------------------------------------------+ | 1 | Chris | Java in Depth With Data Structure | | 3 | Bob | C++ in Depth With Data Structure And Algorithm | +-----------+-------------+------------------------------------------------+ 2 rows in set (0.00 sec)
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