奈寻味导航网 » 文章资讯 » 根据另一列中的DATE值执行MySQL UPDATE

根据另一列中的DATE值执行MySQL UPDATE

2024-04-22 17:34:05 339

让我们首先创建一个表-

mysql> create table DemoTable(
   Id int NOT NULL AUTO_INCREMENT PRIMARY KEY,
   Name varchar(100),
   AdmissionDate date
);

使用插入命令在表中插入一些记录-

mysql> insert into DemoTable(Name,AdmissionDate) values('Chris','2019-11-21');
mysql> insert into DemoTable(Name,AdmissionDate) values('Mike','2019-03-11');
mysql> insert into DemoTable(Name,AdmissionDate) values('Sam','2018-04-01');
mysql> insert into DemoTable(Name,AdmissionDate) values('Carol','2019-05-01');

使用select语句显示表中的所有记录-

mysql> select *from DemoTable;

这将产生以下输出-

+----+-------+---------------+
| Id | Name  | AdmissionDate |
+----+-------+---------------+
|  1 | Chris | 2019-11-21    |
|  2 | Mike  | 2019-03-11    |
|  3 | Sam   | 2018-04-01    |
|  4 | Carol | 2019-05-01    |
+----+-------+---------------+
4 rows in set (0.00 sec)

现在让我们基于特定的DATE值（即2019-04-01此处）更新表-

mysql> update DemoTable set Name='Robert',AdmissionDate='2019-04-01' where Id=3;
Rows matched: 1 Changed: 1 Warnings: 0

让我们再次检查表记录-

mysql> select *from DemoTable;

这将产生以下输出-

+----+--------+---------------+
| Id | Name   | AdmissionDate |
+----+--------+---------------+
|  1 | Chris  | 2019-11-21    |
|  2 | Mike   | 2019-03-11    |
|  3 | Robert | 2019-04-01    |
|  4 | Carol  | 2019-05-01    |
+----+--------+---------------+
4 rows in set (0.00 sec)

返回顶部
3162201930
czq8825@qq.com

根据另一列中的DATE值执行MySQL UPDATE

热门推荐

随机推荐