Java中的ByteBuffer compareTo()方法
可以使用类java.nio.ByteBuffer中的compareTo()方法将一个缓冲区与另一个缓冲区进行比较。如果缓冲区小于给定缓冲区，则此方法返回负整数；如果缓冲区等于给定缓冲区，则返回零；如果缓冲区大于给定缓冲区，则返回正整数。
演示此的程序如下所示-
示例
import java.nio.*;
import java.util.*;
public class Demo {
public static void main(String[] args) {
int n = 5;
try {
ByteBuffer buffer1 = ByteBuffer.allocate(n);
buffer1.put((byte)1);
buffer1.put((byte)2);
buffer1.put((byte)3);
buffer1.put((byte)4);
buffer1.put((byte)5);
buffer1.rewind();
System.out.println("The first ByteBuffer is: " + Arrays.toString(buffer1.array()));
ByteBuffer buffer2 = ByteBuffer.allocate(n);
buffer2.put((byte)1);
buffer2.put((byte)2);
buffer2.put((byte)3);
buffer2.put((byte)4);
buffer2.put((byte)5);
buffer2.rewind();
System.out.println("The second ByteBuffer is: " + Arrays.toString(buffer2.array()));
int val = buffer1.compareTo(buffer2);
if (val == 0)
System.out.println("\nBoth the buffers are lexicographically equal");
else if (val > 0)
System.out.println("\nThe first buffer is lexicographically greater than the second buffer");
else
System.out.println("\nThe second buffer is lexicographically greater than the first buffer");
} catch (IllegalArgumentException e) {
System.out.println("Error!!! IllegalArgumentException");
} catch (ReadOnlyBufferException e) {
System.out.println("Error!!! ReadOnlyBufferException");
}
}
}输出结果
The first ByteBuffer is: [1, 2, 3, 4, 5] The second ByteBuffer is: [1, 2, 3, 4, 5] Both the buffers are lexicographically equal