C#中的Decimal.ToDouble()方法
C#中的Decimal.ToDouble()方法用于将指定的Decimal的值转换为等效的双精度浮点数。
语法
以下是语法-
public static double ToDouble (decimal val);
上面的Val是要转换的十进制数。
示例
现在让我们看一个实现Decimal.ToDouble()方法的示例-
using System; public class Demo { public static void Main(){ Decimal val1 = -0.22m; Decimal val2 = -0.01m; Console.WriteLine("Decimal 1 = "+val1); Console.WriteLine("Decimal 2 = "+val2); Double res1 = Decimal.ToDouble(val1); Double res2 = Decimal.ToDouble(val2); Console.WriteLine("Double value1 (Decimal to Double) = "+res1); Console.WriteLine("Double value2 (Decimal to Double) = "+res2); } }
输出结果
这将产生以下输出-
Decimal 1 = -0.22 Decimal 2 = -0.01 Double value1 (Decimal to Double) = -0.22 Double value2 (Decimal to Double) = -0.01
示例
现在让我们来看另一个实现Decimal.ToDouble()方法的示例-
using System; public class Demo { public static void Main(){ Decimal val1 = 23828m; Decimal val2 = 976587687595766665m; Console.WriteLine("Decimal 1 = "+val1); Console.WriteLine("Decimal 2 = "+val2); Double res1 = Decimal.ToDouble(val1); Double res2 = Decimal.ToDouble(val2); Console.WriteLine("Double value1 (Decimal to Double) = "+res1); Console.WriteLine("Double value2 (Decimal to Double) = "+res2); } }
输出结果
这将产生以下输出-
Decimal 1 = 23828 Decimal 2 = 976587687595766665 Double value1 (Decimal to Double) = 23828 Double value2 (Decimal to Double) = 9.76587687595767E+17