可以在AP中随机选择三个数字的C ++程序概率

2024-05-19 11:36:07 336

示例

Input-: arr[] = { 2,3,4,7,1,2,3 } Output-: Probability of three random numbers being in A.P is: 0.107692 Input-:arr[] = { 1, 2, 3, 4, 5 } Output-: Probability of three random numbers being in A.P is: 0.151515

以下程序中使用的方法如下-

输入正整数数组

计算数组的大小

应用下面给出的公式找出三个随机数出现在AP中的概率

3n/（4（n*n）–1）

打印结果

算法

Start
Step 1-> function to calculate the probability of three random numbers be in  AP
   double probab(int n)
      return (3.0 * n) / (4.0 * (n * n) - 1)
Step 2->In main()
   declare an array of elements as   int arr[] = { 2,3,4,7,1,2,3 }
   calculate size of an array as  int size = sizeof(arr)/sizeof(arr[0])
   call the function to calculate probability as probab(size)
Stop

示例

#include <bits/stdc++.h>
using namespace std;
//calculate probability of three random numbers be in AP
double probab(int n) {
    return (3.0 * n) / (4.0 * (n * n) - 1);
}
int main() {
    int arr[] = { 2,3,4,7,1,2,3 };
    int size = sizeof(arr)/sizeof(arr[0]);
    cout<<"probability of three random numbers being in A.P is : "<<probab(size);
    return 0;
}

输出结果

Probability of three random numbers being in A.P is: 0.107692

可以在AP中随机选择三个数字的C ++程序概率

示例

算法

示例

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