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Python Pandas - 从 DateTimeIndex 创建一个 DataFrame 但覆盖结果列的名称

2024-05-20 15:36:06 326

要从DateTimeIndex创建DataFrame，请使用.我们已经设置了name参数来覆盖结果列的名称。datetimeindex.to_frame()

首先，导入所需的库-

import pandas as pd

创建一个日期时间索引，周期为5，频率为S，即秒-

datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')

显示日期时间索引-

print("DateTimeIndex...\n", datetimeindex)

未使用'False'参数在返回的DataFrame中设置原始索引。为了覆盖结果列的名称，我们使用了'name'参数-

print("\nDateTimeIndex to DataFrame...\n",
datetimeindex.to_frame(index=False, name = 'DateTimeData'))

示例

以下是代码-

import pandas as pd

#DatetimeIndexwithperiod5andfrequencyasSi.e.seconds
#timezoneisAustralia/Adelaide
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')

#displayDateTimeIndex
print("DateTimeIndex...\n", datetimeindex)

#displayDateTimeIndex frequency
print("\nDateTimeIndex frequency...\n", datetimeindex.freq)

#CreateaDataFramefromDateTimeIndex
# The original index isn't set in the returned DataFrame using the 'False' parameter
# To override the name of the resulting column, we have used the 'name' parameter
print("\nDateTimeIndex to DataFrame...\n",
datetimeindex.to_frame(index=False, name = 'DateTimeData'))

输出结果

这将产生以下代码-

DateTimeIndex...
DatetimeIndex(['2021-10-18 07:20:32.261811624+10:30',
'2021-10-18 07:21:12.261811624+10:30',
'2021-10-18 07:21:52.261811624+10:30',
'2021-10-18 07:22:32.261811624+10:30',
'2021-10-18 07:23:12.261811624+10:30'],
dtype='datetime64[ns, Australia/Adelaide]', freq='40S')

DateTimeIndex frequency...
<40 * Seconds>

DateTimeIndex to DataFrame...
DateTimeData
0 2021-10-18 07:20:32.261811624+10:30
1 2021-10-18 07:21:12.261811624+10:30
2 2021-10-18 07:21:52.261811624+10:30
3 2021-10-18 07:22:32.261811624+10:30
4 2021-10-18 07:23:12.261811624+10:30

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Python Pandas - 从 DateTimeIndex 创建一个 DataFrame 但覆盖结果列的名称

示例

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