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Python Pandas - 如何以微秒频率对 DateTimeIndex 执行地板操作

2024-05-20 18:07:06 391

要以微秒频率对DateTimeIndex执行地板操作，请使用方法。对于微秒频率，使用值为'us'的freq参数。DateTimeIndex.floor()

首先，导入所需的库-

import pandas as pd

DatetimeIndex周期为7，频率为S，即秒。时区是澳大利亚/阿德莱德-

datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')

以微秒频率对DateTimeIndex日期进行地板操作。对于微秒频率，我们使用了“我们”-

print("\nPerforming floor operation with microseconds frequency...\n",
datetimeindex.floor(freq='us'))

示例

以下是代码-

import pandas as pd

#DatetimeIndexwithperiod7andfrequencyasSi.e.seconds
#timezoneisAustralia/Adelaide
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')

#displayDateTimeIndex
print("DateTimeIndex...\n", datetimeindex)

#displayDateTimeIndex frequency
print("DateTimeIndex frequency...\n", datetimeindex.freq)

#FlooroperationonDateTimeIndexdatewithmicrosecondsfrequency
# For microseconds frequency, we have used 'us'
print("\nPerforming floor operation with microseconds frequency...\n",
datetimeindex.floor(freq='us'))

输出结果

这将产生以下代码-

DateTimeIndex...
DatetimeIndex(['2021-10-18 07:20:32.261811624+10:30',
'2021-10-18 07:21:12.261811624+10:30',
'2021-10-18 07:21:52.261811624+10:30',
'2021-10-18 07:22:32.261811624+10:30',
'2021-10-18 07:23:12.261811624+10:30'],
dtype='datetime64[ns, Australia/Adelaide]', freq='40S')
DateTimeIndex frequency...
<40 * Seconds>

Performing floor operation with microseconds frequency...
DatetimeIndex(['2021-10-18 07:20:32.261811+10:30',
'2021-10-18 07:21:12.261811+10:30',
'2021-10-18 07:21:52.261811+10:30',
'2021-10-18 07:22:32.261811+10:30',
'2021-10-18 07:23:12.261811+10:30'],
dtype='datetime64[ns, Australia/Adelaide]', freq=None)

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Python Pandas - 如何以微秒频率对 DateTimeIndex 执行地板操作

示例

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