Python Pandas - 如何以秒频率舍入 DateTimeIndex
要以秒频率舍入DateTimeIndex，请使用方法。对于秒频率，使用值为'S'的freq参数。DateTimeIndex.round()
首先，导入所需的库-
import pandas as pd
创建一个日期时间索引，周期为5，频率为s即秒-
datetimeindex = pd.date_range('2021-09-29 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='28s')以秒频率对DateTimeIndex日期进行舍入操作。对于秒频率，我们使用了“S”-
print("\nPerforming round operation with seconds frequency...\n",
datetimeindex.round(freq='S'))示例
以下是代码-
import pandas as pd
#DatetimeIndexwithperiod5andfrequencyassi.e.seconds
#timezoneisAustralia/Adelaide
datetimeindex = pd.date_range('2021-09-29 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='28s')
#displayDateTimeIndex
print("DateTimeIndex...\n", datetimeindex)
#displayDateTimeIndex frequency
print("DateTimeIndex frequency...\n", datetimeindex.freq)
#gettingthesecond
res = datetimeindex.second
#displayonlythesecond
print("\nThe second from DateTimeIndex...\n", res)
#RoundoperationonDateTimeIndexdatewithsecondsfrequency
# For seconds frequency, we have used 'S'
print("\nPerforming round operation with seconds frequency...\n",
datetimeindex.round(freq='S'))输出结果这将产生以下代码-
DateTimeIndex... DatetimeIndex(['2021-09-29 07:20:32.261811624+09:30', '2021-09-29 07:21:00.261811624+09:30', '2021-09-29 07:21:28.261811624+09:30', '2021-09-29 07:21:56.261811624+09:30', '2021-09-29 07:22:24.261811624+09:30'], dtype='datetime64[ns, Australia/Adelaide]', freq='28S') DateTimeIndex frequency... <28 * Seconds> The second from DateTimeIndex... Int64Index([32, 0, 28, 56, 24], dtype='int64') Performing round operation with seconds frequency... DatetimeIndex(['2021-09-29 07:20:32+09:30', '2021-09-29 07:21:00+09:30', '2021-09-29 07:21:28+09:30', '2021-09-29 07:21:56+09:30', '2021-09-29 07:22:24+09:30'], dtype='datetime64[ns, Australia/Adelaide]', freq=None)
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