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Python Pandas - 以单个单位的倍数为频率舍入 DateTimeIndex

2024-05-20 16:01:06 436

要将DateTimeIndex的频率舍入为单个单位的倍数，请使用方法。设置频率的freq参数。DateTimeIndex.round()

首先，导入所需的库-

import pandas as pd

DatetimeIndex周期为5，频率为H即小时-

datetimeindex = pd.date_range('2021-09-29 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='H')

显示日期时间索引-

print("DateTimeIndex...\n", datetimeindex)

以10分钟的频率舍入DateTimeIndex，即单个单位的倍数。对于分钟频率，我们使用了'T-

print("\nPerforming round operation with multiples of a single unit frequency...\n",
datetimeindex.round(freq='10T'))

示例

以下是代码-

import pandas as pd

#DatetimeIndexwithperiod5andfrequencyasHi.e.hours
#timezoneisAustralia/Adelaide
datetimeindex = pd.date_range('2021-09-29 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='H')

#displayDateTimeIndex
print("DateTimeIndex...\n", datetimeindex)

#displayDateTimeIndex frequency
print("DateTimeIndex frequency...\n", datetimeindex.freq)

#RoundaDateTimeIndexwith10minutesfrequencyi.e.multiplesofasingleunit
# For minutes frequency, we have used 'T'
print("\nPerforming round operation with multiples of a single unit frequency...\n",
datetimeindex.round(freq='10T'))

输出结果

这将产生以下代码-

DateTimeIndex...
DatetimeIndex(['2021-09-29 07:20:32.261811624+09:30',
'2021-09-29 08:20:32.261811624+09:30',
'2021-09-29 09:20:32.261811624+09:30',
'2021-09-29 10:20:32.261811624+09:30',
'2021-09-29 11:20:32.261811624+09:30'],
dtype='datetime64[ns, Australia/Adelaide]', freq='H')
DateTimeIndex frequency...
<Hour>

Performing round operation with multiples of a single unit frequency...
DatetimeIndex(['2021-09-29 07:20:00+09:30', '2021-09-29 08:20:00+09:30',
'2021-09-29 09:20:00+09:30', '2021-09-29 10:20:00+09:30',
'2021-09-29 11:20:00+09:30'],
dtype='datetime64[ns, Australia/Adelaide]', freq=None)

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Python Pandas - 以单个单位的倍数为频率舍入 DateTimeIndex

示例

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